LeetCode problem 2566: Maximum Difference by Remapping a Digit involves remapping one digit in a number to find the maximum difference between the largest and smallest number possible.
The problem allows Bob to change one digit (0–9) to any other digit, including itself, and aims to maximize the difference between the resulting numbers.
The key approach is to change the leftmost significant digits to impact the number the most, ensuring a larger shift for maximum difference.
In C++, the solution involves finding the first non-'9' digit and the first digit, then replacing them to compute the maximum and minimum values for the difference.
The JavaScript and Python versions also follow similar logic to find and replace digits to calculate the difference.
Test cases demonstrate how the algorithm works for different inputs, producing the correct maximum differences.
The time complexity for this problem is O(n), where n is the number of digits, as it involves a single pass for replacement.
Space complexity is O(1) as only a few variables are used during the computation.
This problem is a great exercise for understanding greedy digit manipulation and string traversal techniques, emphasizing maximizing by changing the first non-'9' digit to '9' and minimizing by changing the first digit to '0'.
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