<ul data-eligibleForWebStory="true"><li>LeetCode problem 2200 involves finding all k-distant indices in an array, where an index i is considered k-distant if there is at least one index j such that |i - j| <= k and nums[j] == key.</li><li>The efficient solution for this problem involves a greedy strategy using pointers, where for each index j where nums[j] == key, all indices i within [j - k, j + k] are added to the result set, covering all valid i within the distance k from the key position.</li><li>The C++, JavaScript, and Python solutions provided linearly process the array, ensuring old indices are not rechecked, resulting in a time complexity of O(n) and space complexity of O(1) apart from the output.</li></ul>

🌋 Find All K-Distant Indices in an Array – LeetCode 2200 (C++ | Python | JavaScript)

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