<ul data-eligibleForWebStory="false"><li>The problem involves rescheduling up to k meetings to maximize the longest continuous free time within a given event window.</li><li>The approach includes calculating all gaps between meetings, sliding a window of size k+1 over the gaps, and tracking the maximum sum of k+1 consecutive gaps.</li><li>C++ and Python code solutions are shared that implement the logic of calculating gaps and finding the maximum free time.</li><li>The time complexity of the solution is O(n), and the space complexity is O(n). This problem can be solved by using a sliding window technique over the gaps array.</li></ul>

🐨Beginner-Friendly Guide "Maximize Free Time by Rescheduling Meetings" – LeetCode 3439 (C++ | Python | JavaScript)

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