<ul><li>To solve LeetCode 42: Trapping Rain Water, we need to calculate the total amount of water that can be trapped between elevation heights after it rains.</li><li>This problem is best tackled using the two-pointer approach, which has O(n) time complexity and O(1) space complexity.</li><li>The implementation of the solution involves initializing two pointers and two variables to store the maximum height seen so far from the left and right.</li><li>Then, the algorithm compares the heights at the left and right pointers, calculates the water trapped based on the maximum heights, and moves the pointers inward until they meet.</li></ul>

LeetCode Challenge: 42. Trapping Rain Water - JavaScript Solution 🚀

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