<ul data-eligibleForWebStory="false">Given a circular integer array, the task is to find the next greater element for each element in the array.The next greater element is the first element greater than the current element when traversing the circular array.To solve this, we use a stack to keep track of indices and simulate the circular nature by iterating from 0 to 2*n - 1.Time complexity is O(n), space complexity is O(n).