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Here's How Developers Can Ensure Sensitive Data Does Not Accidentally Reach Another Device

As application developers, it is your job to ensure that sensitive data stored in your application does not get accidentally delivered to another party.
Row-level security (RLS) is the ability to secure and control access to specific rows of data inside a database table.
Neon Authorize streamlines the process of correctly implementing RLS by automatically integrating authentication from OAuth provider with PostgreSQL database.
The tutorial walks the users through how to build a Remix app using Clerk as an authentication layer.
Add Row Layer Security to your app today with Neon.
Our sample application is simple—it records every login into the RLS database, using the userID. When the page is loaded, the last 10 logins for the authenticated user will be displayed, and no other user’s data (stored in the same PostgreSQL table) will appear.
To protect sensitive data stored in applications, Neon Authorize provides an automatic integration of OAuth authentication providers like Clerk with PostgreSQL databases and provides Row-Level Security (RLS).
The LoaderFunction in the _index.tsx file completes tasks on the server before rendering the page for the client.
The LoaderFunction first checks if the user is not logged in and then redirects the user to the /sign-in page.
The Index() function in _index.tsx file renders the layout of the page.

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Dev

328

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Set up Anaconda on Ubuntu 22.04 in Minutes: Simplify Your AI Workflow

Anaconda is a powerful library that simplifies managing packages, dependencies, and environments for Python-based projects.
This guide provides step-by-step instructions on installing Anaconda on Ubuntu 22.04 using an installer script and initializing the conda environment.
The guide assumes that the user has a virtual machine with a certain specification, such as 2 vCPUs, 4 GB RAM, and a 20 GB SSD.
The user needs to create a NodeShift account, create a compute node, configure and select image for a virtual machine, choose the billing cycle and authentication method and finalize the details and create the deployment.
Once the VM is running, the user can connect to the active Compute Node using SSH and download the Anaconda installer.
The user needs to verify the installer script, install Anaconda using the bash command, initialize Anaconda, add Anaconda functions, and finally, verify the installation.
Anaconda is useful for data science, machine learning, or managing AI projects, and this guide simplifies the process of setting it up on Ubuntu.
By deploying the Ubuntu server on NodeShift, users can have optimized energy consumption, scalability, and enhanced performance, making it the ideal choice for deploying resource-intensive tools like Anaconda in a sustainable and efficient manner.
NodeShift's infrastructure ensures a smooth and reliable setup for Anaconda to get your environment ready for efficient development.
This guide provides a convenient method for setting Anaconda on Ubuntu for anyone looking to power up their data science or machine learning workflows.

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Dev

211

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SOLID: The Interface Segregation Principle(ISP) in C#

The Interface Segregation Principle (ISP) ensures that no client is forced to depend on methods it does not use.
Large interfaces should be broken down into smaller, more specific interfaces to prevent burdening classes with irrelevant functionality.
Example: A large interface called IAnimal is split into smaller interfaces such as IEater, IFlyer, and ISwimmer to allow classes to implement only the interfaces they need.
Benefits of following ISP include avoiding unnecessary methods, improved maintainability, and better flexibility.

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Prodevelopertutorial

159

Given a string s, partition s such that every substring of the partition is a palindrome.

The given problem is to partition a string into palindromic substrings.
The solution involves using depth-first search (DFS) to find all possible palindromic substrings.
The code implementation is provided in C++.
The result is a vector of vectors, where each inner vector represents a palindromic partition.

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Hackernoon

366

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Understanding Parallel Programming: Thread Management for Beginners

In this fourth part of the series Understanding Parallel Programming: A Guide for Beginners, the author discusses Thread management, Thread execution flags, and Thread priority management tool.
Thread management involves managing the execution and stopping it for which the article provides code snippets. The catch though is that a Thread cannot be stopped; it can only be given an order to stop and needs to be coded accordingly.
Thread execution flags indicate the state of the thread. There are three flags namely – isExecuting, isCancelled, and isFinished. The developer must track isCancelled and stop the thread if it is true. isFinished flag indicates whether the thread has completed its execution.
Thread priority management, on the other hand, enables us to prioritise certain threads based on their resource needs. It helps manage threads based on their resource demands and optimise the usage and prevent UI lags.
The article also emphasises that merely adding more threads doesn’t always resolve performance issues. Even with hundreds of threads, you're still limited by the device's resources.
Lastly, Run Loop, by default, is only present in the main thread and not automatically available in any other threads you create. It is essential for managing asynchronous code, timers, and some notifications like Realm, as they may not work properly in secondary threads.
The author provides several code snippets demonstrating how to work with RunLoop in Threads. Understanding the concepts and the examples provided is essential for efficient multithreading in iOS applications.
The article concludes with a mention that in the next part of the series, the author will discuss Grand Central Dispatch library (GCD) that simplifies thread management.

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Prodevelopertutorial

Surrounded Regions

A region is captured by flipping all ‘O’s into ‘X’s in that surrounded region.
The solution here is very simple. First we check if any of the edges of row and column is ‘o’ and also check if their neighbour is also ‘o’ then replace them with the character “1”.
Then we convert all the remaining ‘o’ to ‘x’ and replace ‘1’ with ‘o’. We get our solution.
The steps can be pictorially shown as below: X X X X X X X X X X X X X O O X ---> X O O X -then-> X X X X X X O X X X O X X X X X X O X X X 1 X X X O X X

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Dev

320

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🔥 Must-See: 20+ New Open Source GitHub Repositories You Can’t Miss! (Dec 25, 2024)

Btop: A Monitor of Resources
Augini, an AI-Powered Tabular Data Assistant
RCMP: Reconstructing RDMA-Based Memory Disaggregation via CXL
ECAL – Enhanced Communication Abstraction Layer / Pub-Sub Middleware

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Prodevelopertutorial

Best time to buy sell stock

To find the best time to buy and sell stocks and maximize profit, we use the concept of minPrice and maxProfit.
minPrice represents the minimum price from day 0 to current day, while maxProfit represents the maximum profit from day 0 to current day.
Using a loop, we update the minPrice and maxProfit values based on the current day's price.
Finally, we return the calculated maxProfit as the result.

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Medium

215

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Implementing Conway’s Game of Life in C++

Conway’s Game of Life is a powerful way to simulate complex systems.
The game considers a cell's neighbors using Moore's neighborhood.
The algorithm updates the entire grid based on specific rules.
The implementation in C++ using raylib simplifies graphics programming.

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Prodevelopertutorial

Given a triangle, find the minimum path sum from top to bottom.

Given a triangle, find the minimum path sum from top to bottom.
Two approaches to solve the problem: Top Down and Bottom Up.
Top Down approach: Initialize a result vector with the value of triangle[0][0]. Iterate through the levels and compute the minimum path sum.
Bottom Up approach: Start from the row above the bottom row. Add the smaller of the two adjacent numbers with the current element. Get the smallest sum to the top.

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Prodevelopertutorial

280

Check if the given board is valid Sudoku or not explanation with solution in CPP

To determine if a 9×9 Sudoku board is valid, we need to check if each row, column, and 3x3 sub-box contains the digits 1-9 without repetition.
We can use a boolean matrix to keep track of the numbers that have appeared in each row, column, and sub-box.
Iterate through the board and update the boolean matrix accordingly.
If there are no duplicates, the Sudoku board is valid.

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Prodevelopertutorial

220

Given a non-negative integer numRows, generate the first numRows of Pascal’s triangle.

Input: 5
Output:
[
[1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1]
]
In each row, the first and last element are 1. And the other element is the sum of the two elements in the previous row.
This problem can be solved by iterating through each row and calculating each element in the row as the sum of the corresponding elements in the previous row.
The given code snippet demonstrates the solution in C++.

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Prodevelopertutorial

164

Restore IP Addresses

Given a string containing only digits, restore it by returning all possible valid IP address combinations.
The solution for this problem can be done using an iterative/brute force approach or a recursive/DFS approach.
The iterative approach involves checking all possible combinations of parts that form a valid IP address.
The recursive approach involves constructing the IP address by considering valid parts and backtracking when necessary.

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Prodevelopertutorial

185

Reverse a linked list from position m to n. Do it in one-pass.

To reverse a linked list from position m to n, we need to use 4 pointers.
The 4 pointers used are: new_head, pre, cur, and Move.
We set the first 3 pointers and start reversing the list by changing the immediate node after 'cur'.
The solution in C++ provides the implementation of reversing a linked list from position m to n.

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Prodevelopertutorial

336

Decode Ways

A message containing letters from A-Z is being encoded to numbers using the following mapping: ‘A’ -> 1 ‘B’ -> 2 … ‘Z’ -> 26
Given a non-empty string containing only digits, determine the total number of ways to decode it.
Example 1: Input: “12” Output: 2 Explanation: It could be decoded as “AB” (1 2) or “L” (12).
Example 2: Input: “226” Output: 3 Explanation: It could be decoded as “BZ” (2 26), “VF” (22 6), or “BBF” (2 2 6).

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